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A thin semicircular conducting ring of radius `R` is falling with its plane verticle in a horizontal magnetic inducting `B`. At the position `MNQ`, the speed of the ring is `V` and the potential difference developed across the ring is

(1.) zero
(2.)`BcpiR^(2)//2`
(3.) `piRBV`
(4.) `2RBV`

A

zero

B

`BvR^(2)/2` and M is at higher potential

C

`(W_(1))/(W_(2))=4`

D

`(W_(1))/(W-(2)=(1)/(16))`

Text Solution

Verified by Experts

The correct Answer is:
4

The induced emf as given by Faraday.s law of induction is`E=-Blv`
`l=2R`
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