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In an AC circuit , the potential differe...

In an AC circuit , the potential difference V and current I are given respectively by
V = 100sin(100t)V
and l = 100sin(100t + `pi`/3)mA
The power dissipated in the circuit will be

A

watt

B

10 watt

C

2.5 watt

D

5 watt.

Text Solution

Verified by Experts

The correct Answer is:
3
`P=V_(rms)I_(rms)cosphi=(100)/(sqrt2)((100)/(sqrt2)xx10^(-3))cos60^(@)=(10)/(2)xx(1)/(2)=2.5watt`
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