In an ac circuit , `L = (0.4)/(pi) H` and `R = 30 Omega`. If the circuit has an alternating emf of 200 V, 50 cps, the impedance and the current in the circuit will be :

Options

A. 11.4 ohm, 17.5 ampere
B. 30.7 ohm, 6.5 ampere
C. 40.4 ohm,5 ampere
D. 50 ohm, 4 ampere

Answer

4

Explanation

Here`X_(L)=omegaL=2pifL=2pixx50xx(0..4)/(pi)=40Omega`
`R=30Omega`
`Z=(sqrtR_(2)+X^(2)_(L)=sqrt30^(2)+40^(2)=50Omega)`,
`I_(rnms)=(V_(rms)=(200)/(50)=4A`