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In case of a.c circuit, Ohm's law holds ...

In case of `a.c` circuit, Ohm's law holds good for
`{:a)` Peak values of voltage and current
`{:b)` Effective values of voltage and current
`{:c)` Instantaneous values of voltage and current

A

only (a) and (b)

B

only (a)

C

only (c) is true

D

(a), (b) and (c) are true

Text Solution

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The correct Answer is:
To solve the question regarding Ohm's law in an AC circuit, we need to analyze how Ohm's law applies to different types of values: peak values, effective (RMS) values, and instantaneous values of voltage and current. ### Step-by-Step Solution: 1. **Understanding Ohm's Law**: Ohm's law states that \( V = I \cdot R \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance. This law applies to both DC and AC circuits, but we need to determine for which values it holds true in an AC circuit. 2. **Defining AC Voltage and Current**: In an AC circuit, the voltage and current can be expressed as: - Voltage: \( v(t) = V_0 \sin(\omega t + \phi) \) - Current: \( i(t) = I_0 \sin(\omega t) \) Here, \( V_0 \) and \( I_0 \) are the peak (maximum) values of voltage and current, respectively. 3. **Calculating Effective (RMS) Values**: The effective (RMS) values for voltage and current in an AC circuit are given by: - \( V_{\text{RMS}} = \frac{V_0}{\sqrt{2}} \) - \( I_{\text{RMS}} = \frac{I_0}{\sqrt{2}} \) 4. **Applying Ohm's Law**: - For peak values: \[ V_0 = I_0 \cdot R \] This shows that Ohm's law holds for peak values of voltage and current. - For effective values: \[ V_{\text{RMS}} = I_{\text{RMS}} \cdot R \] This indicates that Ohm's law also holds for effective values of voltage and current. - For instantaneous values: The instantaneous values of voltage and current vary with time and do not maintain a constant relationship as defined by Ohm's law. 5. **Conclusion**: Based on the analysis: - Ohm's law holds for peak values (Option A) and effective values (Option B) of voltage and current. - It does not hold for instantaneous values (Option C). Thus, the correct answers are **Option A (Peak values of voltage and current)** and **Option B (Effective values of voltage and current)**.
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