Home
Class 12
PHYSICS
An ideal coil of 10 H is joined in serie...

An ideal coil of 10 H is joined in series with a resistance of `5Omega` and a battery of 5 V. 2 s after joining, the current flowing in ampere in the circuit will be

A

`e^(-1)`

B

`(1-e^(-1))`

C

(1-e)

D

e

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-D|10 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-E|10 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-B|10 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) Level - II (SINGLE OPTION CORRECT TYPE )|31 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATIVE CURRENT

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

Similar Questions

Explore conceptually related problems

An ideal coil of 10 henry is joined in series with a resistance of 5 ohm and a battery of 5 volt. 2 second after joining, the current flowing in ampere in the circuit will be

An idal coil of 10 is connected in series with a resitance of 5Omega and a battery of 5V. After 2s, after the connection is made, the current flowing ( in ampere) in the circuit is

In the circuit in figure, the current flowing 5 Omega resistance is :

A galvanometer of resistance 95 Omega , shunted resistance of 5 Omega , gives a deflection of 50 divisions when joined in series with a resistance of 20 k Omega and a 2 V accumulator. What is the current sensitivity of the galvanomter (in div //mu A )?

An inductor of 2 H and a resistance of 10Omega are connects in series with a battery of 5 V. The initial rate of change of current is

A coil has inductance of (11)/(5pi)H and is joined in series with a resistance of 220Omega . When an alternating emf of 220V at 50Hz is applied to it, then the wattless component of the current in the circuit is

A coil has an inductance of 22/pi H and is joined in series with a resistance of 220 Omega .When an alternating e.m.f of 220 V at 50 c.p.s is applied to it.then the wattless component of the rms current in the circuit is

A coil has a inductance of 0.7pi H and is joined in series with a resistance of 220 Omega . When an alternating emf of 220V at 50 cps is applied to it, then the watt-less component of the current in the circuit is (take 0.7pi = 2.2)

A coil of 40 H inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 V battery. The time constant of the circuit

in the figure shown , a circuit contains two identical resistors with resistance R= Omega and an inductance with L=2 H ,An ideal battery of 15 V is connected in the circuit what will be the current through the battery long after the switch is clossed ?