A ray of light is icncident at anangle of `60^@` on one face of a ractangular glass slab of thickness `2sqrt(3)` mm refractive index `sqrt(3)` , Calculate the lateral shift produced in mm.

Explanation

To calculate the lateral shift produced by a ray of light incident at an angle of 60° on one face of a rectangular glass slab with a thickness of \(2\sqrt{3}\) mm and a refractive index of \(\sqrt{3}\), we can follow these steps:

### Step 1: Identify the given values
- Incident angle (\(i\)) = 60°
- Thickness of the glass slab (\(d\)) = \(2\sqrt{3}\) mm
- Refractive index (\(\mu\)) = \(\sqrt{3}\)

### Step 2: Apply Snell's Law
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