An equilateral prism is made of glass of refractive index 1.5. Calculate the angles of minimum and maximum deviation. Given:
`A=60^@, mu=1.5, sin48.6^@=(3)/(4), sin41.8^@=(3)/(2), sin27.9^@=(3)/(2)sin18.2`

Explanation

The angle of minimum deviation occurs when i = e and `r = r_(2)` and is given by
`mu=(sin((A+delta_(m))/2))/(sin(A/2))`
`implies delta_(m)=2sin^(-1)(musin(A/2))-A`
Substituting `mu` = 1.5 and `A = 60^@`, we get
`delta_(m)=2sin^(-1)(0.75)-60^@=37^@`
Maximum deviation: