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In YDSE, the amplitude of intensity vari...

In YDSE, the amplitude of intensity variation for the two sources is found to be `5%` of the average intensity. The ratio of the intensities of two interfering sources is

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`i_(max)/i_(min) =105/95 =21/19` or `((a_(1)+ a_(2))^(2))/((a_(1)-a_(2))^(2))=21/19`
`(a_(1)+a_(2))/(a_(1)-a_(2))=sqrt(21/19)=1.05` or `a_(1)+a_(2)=1.05 a_(1)-1.05a_(2)`
`0.05a_(1)=2.05a_(2)` or `a_(1)/a_(2)=2.05/0.05=41/1 therefore I_(1)/I_(2) =a_(1)^(2)/a_(2) =1680/1`
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