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In the Young's double slit experiment, t...

In the Young's double slit experiment, the intensity of light at a point on the screen (where the path difference is `lambda`) is K, (`lambda` being the wavelength of light used ). The intensity at a point where the path difference is `lambda//4` will be

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`phi_(1) =(2pid)/lambda implies (2pi)/lambda xxlambda=2pi` and `phi_(2)=(2pi)/lambda xx lambda/4 =pi/2`
`I_(1)=I_(0)+i_(0)+2sqrt(I_(0))sqrt(I_(0))cos2pi =4I_(0)` and `I_(2)=I_(0)+I_(0)+ 2sqrt(I_(0))sqrt(I_(0)) cos(pi/2)=2I_(0)`
`therefore I_(1)/I_(2) =(4I_(0))/(2I_(0)) =2 implies I_(2) =I_(1)/2 =K/2` unit [`because I_(1)=K` unit]
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