In Young's double slit experiment the fringe are formed at a distance of 1 m from double slits of separation 0.12 mm. Calculate
The distance of 3rd bright band from the centre of the screen, given `lamda=6000A`

Explanation

To solve the problem of finding the distance of the 3rd bright band from the center of the screen in Young's double slit experiment, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Wavelength (\(\lambda\)) = 6000 Å = \(6000 \times 10^{-10}\) m = \(6 \times 10^{-7}\) m
- Distance between the slits (\(d\)) = 0.12 mm = \(0.12 \times 10^{-3}\) m = \(1.2 \times 10^{-4}\) m
- Distance from the slits to the screen (\(D\)) = 1 m
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