In young's double slit experiment the slits are illumated by light of wavelength `5890^(@)` A and the angular distance between the fringes obtained on the screen is `0.2^(@)`. If the whole apparatus is immersed in water then the angular fringe width will be, if the refractive index of water is `4//3`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the relationship between angular fringe width and wavelength
In Young's double slit experiment, the angular width (θ) of the fringes is directly proportional to the wavelength (λ) of the light used. The relationship can be expressed as:
\[ \theta = \frac{\lambda}{d} \]
where \(d\) is the distance between the slits.
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