When light travels from glass to air, the incident angle is `theta_(1)` and the refracted angle is `theta_(2)`. The true relation is

Options

A. (a)`theta_(1)=theta_(2)`
B. (b)`theta_(1) lttheta_(2)`
C. (c)`theta_(1) ge theta_(2)`
D. (d)Not predictable

Answer

To solve the problem of light traveling from glass to air, we can use Snell's Law, which relates the angles of incidence and refraction to the indices of refraction of the two media involved.

### Step-by-Step Solution:

1. **Identify the Media**:
- The first medium is glass (denser medium) with a refractive index \( n_1 \).
- The second medium is air (rarer medium) with a refractive index \( n_2 \).

2. **Understand the Angles**:
- Let \( \theta_1 \) be the angle of incidence in the glass.
- Let \( \theta_2 \) be the angle of refraction in the air.

3. **Apply Snell's Law**:
- Snell's Law states:
\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]

4. **Refractive Indices**:
- The refractive index of glass is typically greater than that of air. For example, \( n_{glass} \approx 1.5 \) and \( n_{air} \approx 1.0 \).

5. **Rearranging Snell's Law**:
- From Snell's Law, we can express the relationship between the angles:
\[ \sin(\theta_2) = \frac{n_1}{n_2} \sin(\theta_1) \]
- Since \( n_1 > n_2 \), it follows that \( \sin(\theta_2) > \sin(\theta_1) \).

6. **Angle Comparison**:
- Since the sine function is increasing in the range of \( 0^\circ \) to \( 90^\circ \), we conclude that:
\[ \theta_2 > \theta_1 \]

7. **Final Conclusion**:
- Therefore, the true relation when light travels from glass to air is:
\[ \theta_2 > \theta_1 \]