Home
Class 12
PHYSICS
In a compound microscope the objective o...

In a compound microscope the objective of `f_(o)` and eyepiece of `f_(e)` are placed at distance `L` such that `L` equals

A

`f_(o)+f_(e)`

B

`f_(0)-f_(e)`

C

Much greater than `f_(0)` or `f_(e)`

D

Need not depend either value of focal lengths

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance \( L \) between the objective lens and the eyepiece in a compound microscope, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - A compound microscope consists of two convex lenses: the objective lens (with focal length \( f_o \)) and the eyepiece (with focal length \( f_e \)). - The objective lens is placed close to the object, and the eyepiece is placed near the eye of the observer. 2. **Image Formation by Objective Lens**: - The objective lens forms a real, inverted, and magnified image of the object. Let’s denote the distance between the objective lens and the eyepiece as \( L \). - The distance \( L \) can be expressed in terms of the focal lengths of the lenses. 3. **Using Lens Formula**: - For the objective lens, the image distance \( v_o \) and object distance \( u_o \) can be related using the lens formula: \[ \frac{1}{f_o} = \frac{1}{v_o} - \frac{1}{u_o} \] - The image formed by the objective lens acts as an object for the eyepiece. 4. **Image Formation by Eyepiece**: - The eyepiece forms a virtual image, which is further magnified. The distance between the two lenses \( L \) can be expressed as: \[ L = f_o + f_e \] - This is because the total distance is the sum of the focal lengths of both lenses when they are in a compound microscope setup. 5. **Condition for L**: - It is important to note that \( L \) must be much greater than either \( f_o \) or \( f_e \) to ensure proper functioning of the microscope. - Therefore, we can state: \[ L \gg f_o \quad \text{and} \quad L \gg f_e \] 6. **Final Expression**: - Thus, the distance \( L \) can be summarized as: \[ L = f_o + f_e \] - This indicates that the distance between the two lenses in a compound microscope is the sum of their focal lengths.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RAY OPTICS

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-6|5 Videos
  • RAY OPTICS

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-7|6 Videos
  • RAY OPTICS

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-4|3 Videos
  • QUIZ

    VMC MODULES ENGLISH|Exercise PHYSICS|30 Videos
  • RAY OPTICS AND WAVE OPTICS

    VMC MODULES ENGLISH|Exercise IMPECCABLE|58 Videos

Similar Questions

Explore conceptually related problems

In case of a simple microscope, the object is placed at

A compound microscope has an objective of focal length 1 cm and an eyepiece of focal length 2.5 cm. An object has to be placed at a distance of 1.2 cm away from the objective for normal adjustment. a.Find the angular magnification. b.Find the length of the microscope tube.

Draw the labelled ray diagram for the formation of image by a compound microscope. Derive the expression for the total magnification of a compound microscope. Explain why both the objective and the eyepiece of a compound microscope must have short focal lengths.

The focal length of the objective of a compound microscope is f_0 and its distance from the eyepiece is L. The object is placed at a distance u from the objective. For proper working of the instrument.,

A compound microscope consists of an objective of focal length 1 cm and an eyepiece of focal length 5 cm. An object is placed at a distance of 0.5 cm from the objective. What should be the separation between the lenses so that the microscope projects an inverted real image of the object on a screen 30 cm behind the eyepiece?

A compound microscope has objective of focal length 3.2 mm and eyepiece of 12 mm focal length. If the objective forms image of the object 16 cm beyond its pole, then total magnification achieved is

The focal length of objective and the eyepiece of a compound microscope are 1cm and 5cm. An object is placed at a distance of 1.1 cm from the objective and if the final image is formed at infinity the magnifying power and distance between the lenses are respectively

The two lenses of a compound microscope are of focal lengths 2 cm and 5 cm. If an object is placed at a distance of 2.1 cm from the objective of focal length 2 cm the final image forms at the final image forms at the least distance of distinct vision of a normal eye. Find the magnifying power of the microscope.

A compound microscope uses an objective lens of focal length 4 cm and eye lens of focal length 10 cm . An object is placed at 6 cm from the objective lens. Calculate magnifying power of compound microscope if final image is formed at the near point. Also, calculate length of the tube of compound microscope.

A compound microscope has tube length 300 mm and an objective of focal length 7.5 mm and an eyepiece of certain focal length. When eyepiece is replaced by another lens of focal length 20 mm, the magnifying power of compound microscope is increased by 100. The focal length of previous eyepiece is