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Least distance of distinct vision is 25 ...

Least distance of distinct vision is 25 cm . Magnifying power of simple microscope of focal length 5 cm is

A

43835

B

5

C

43836

D

6

Text Solution

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The correct Answer is:
To find the magnifying power of a simple microscope with a given focal length, we can use the formula for magnification: ### Step-by-Step Solution: 1. **Identify the Given Values**: - Least distance of distinct vision (d) = 25 cm - Focal length of the microscope (f) = 5 cm 2. **Use the Magnification Formula**: The formula for magnification (M) of a simple microscope is given by: \[ M = 1 + \frac{d}{f} \] 3. **Substitute the Values into the Formula**: Substitute the values of d and f into the magnification formula: \[ M = 1 + \frac{25 \text{ cm}}{5 \text{ cm}} \] 4. **Calculate the Fraction**: Calculate the fraction: \[ \frac{25}{5} = 5 \] 5. **Add 1 to the Result**: Now, add 1 to the result from the previous step: \[ M = 1 + 5 = 6 \] 6. **Final Answer**: Therefore, the magnifying power of the simple microscope is: \[ M = 6 \]
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