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In a laboratory four convex lenses L(1),...

In a laboratory four convex lenses `L_(1), L_(2), L_(3)` and `L_(4)` of focal lengths `2,4,6` and `8 cm` respectively are available. Two of these lenses form a telescope of length `10 cm` and magnifying power 4 . The objective and eye lenses are

A

`L_(2),L_(3)`

B

`L_(1),L_(4)`

C

`L_(3),L_(2)`

D

`L_(4),L_(1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine which of the lenses \( L_1, L_2, L_3, \) and \( L_4 \) are used as the objective and eyepiece of the telescope based on the given information about the focal lengths and the properties of the telescope. ### Step-by-Step Solution: 1. **Identify the Focal Lengths:** - The focal lengths of the lenses are: - \( L_1: 2 \, \text{cm} \) - \( L_2: 4 \, \text{cm} \) - \( L_3: 6 \, \text{cm} \) - \( L_4: 8 \, \text{cm} \) 2. **Set Up the Equations:** - The total length of the telescope is given as \( 10 \, \text{cm} \). This length is the sum of the focal lengths of the objective lens (\( F_o \)) and the eyepiece (\( F_e \)): \[ F_o + F_e = 10 \quad \text{(Equation 1)} \] 3. **Use the Magnifying Power:** - The magnifying power (\( M \)) of the telescope is given as \( 4 \). The magnifying power is defined as the ratio of the focal length of the objective lens to the focal length of the eyepiece: \[ M = \frac{F_o}{F_e} = 4 \quad \text{(Equation 2)} \] 4. **Express \( F_o \) in terms of \( F_e \):** - From Equation 2, we can express \( F_o \) as: \[ F_o = 4 F_e \] 5. **Substitute \( F_o \) into Equation 1:** - Substitute \( F_o \) from the previous step into Equation 1: \[ 4 F_e + F_e = 10 \] - This simplifies to: \[ 5 F_e = 10 \] 6. **Solve for \( F_e \):** - Dividing both sides by \( 5 \): \[ F_e = 2 \, \text{cm} \] 7. **Find \( F_o \):** - Now substitute \( F_e \) back into the equation for \( F_o \): \[ F_o = 4 F_e = 4 \times 2 = 8 \, \text{cm} \] 8. **Identify the Lenses:** - From the focal lengths given: - \( F_e = 2 \, \text{cm} \) corresponds to \( L_1 \) - \( F_o = 8 \, \text{cm} \) corresponds to \( L_4 \) 9. **Conclusion:** - Therefore, the objective lens is \( L_4 \) and the eyepiece lens is \( L_1 \). ### Final Answer: - The objective lens is \( L_4 \) (focal length 8 cm) and the eyepiece lens is \( L_1 \) (focal length 2 cm).
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