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In a wave, the path difference correspon...

In a wave, the path difference corresponding to a phase difference of `phi` is

A

`pi/(2lambda) phi`

B

`pi/lambda phi`

C

`lambda/(2pi) phi`

D

`lambda/pi phi`

Text Solution

AI Generated Solution

The correct Answer is:
To find the path difference corresponding to a phase difference of \( \phi \), we can follow these steps: ### Step 1: Understand the relationship between phase difference and wavelength The phase difference \( \phi \) in a wave is related to the path difference \( \Delta x \) by the equation: \[ \phi = \frac{2\pi}{\lambda} \Delta x \] where \( \lambda \) is the wavelength of the wave. ### Step 2: Rearranging the equation We can rearrange the equation to express the path difference \( \Delta x \) in terms of the phase difference \( \phi \): \[ \Delta x = \frac{\lambda}{2\pi} \phi \] ### Step 3: Final expression Thus, the path difference corresponding to a phase difference of \( \phi \) is given by: \[ \Delta x = \frac{\lambda}{2\pi} \phi \] ### Conclusion The path difference corresponding to a phase difference of \( \phi \) is \( \frac{\lambda}{2\pi} \phi \). ---
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