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In a first order reaction, the concentra...

In a first order reaction, the concentration of the reactant decreases form `800 "mol dm"^(-3)` to `50 "mol dm"^(-3)` in `2 xx 10^(4) s`. The rate constant of the reaction (in `s^(-1)`) is

A

`2 xx 10^4`

B

`3.45 xx 10^(-5)`

C

`1.386 xx 10^(-4)`

D

`2xx 10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
A
For first order reaction :
`k = 2.303/t log""(A_0)/(A_t) = 2.303/(2xx 10^4)log""800/50 = 1.386 xx 10^(-4)s^(-1)`
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