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The concentration of a reactant decrea...

The concentration of a reactant decreases from 0.2 M to 0.1 M in 10 minutes . The rate of the reaction is ______.

A

0.01 M

B

`10^(-2)`

C

`0.01 mol dm^(-3) "min"^(-1) `

D

1 mol

Text Solution

AI Generated Solution

The correct Answer is:
To find the rate of the reaction, we can follow these steps: ### Step 1: Identify the initial and final concentrations - The initial concentration of the reactant is given as \( [A]_0 = 0.2 \, \text{M} \). - The final concentration after the reaction is \( [A]_t = 0.1 \, \text{M} \). ### Step 2: Calculate the change in concentration - The change in concentration (\( \Delta [A] \)) can be calculated as: \[ \Delta [A] = [A]_0 - [A]_t = 0.2 \, \text{M} - 0.1 \, \text{M} = 0.1 \, \text{M} \] ### Step 3: Identify the time interval - The time interval (\( \Delta t \)) during which this change occurs is given as \( 10 \, \text{minutes} \). ### Step 4: Calculate the rate of reaction - The rate of reaction (\( r \)) is defined as the change in concentration over the change in time: \[ r = \frac{\Delta [A]}{\Delta t} = \frac{0.1 \, \text{M}}{10 \, \text{minutes}} = 0.01 \, \text{M/min} \] ### Step 5: Write the final answer with units - Thus, the rate of the reaction is: \[ r = 0.01 \, \text{M/min} \] ### Final Answer: The rate of the reaction is \( 0.01 \, \text{M/min} \). ---
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