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The rate law for the reaction Sucrose +...

The rate law for the reaction Sucrose + Water `overset([H^(+)])to` Glucose + Fructose is given by :

A

Rate = K [sucrose] [water]

B

Rate = K [sucrose] `["water"]^0`

C

Rate = K `["sucrose"]^0` [water]

D

Rate = K `["sucrose"]^(1//2) ["water"]^(1//2)`

Text Solution

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The correct Answer is:
To derive the rate law for the hydrolysis of sucrose in the presence of water and H+, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction is given as: \[ \text{Sucrose} + \text{Water} \overset{[H^+]}{\rightarrow} \text{Glucose} + \text{Fructose} \] Here, sucrose (C12H22O11) reacts with water (H2O) in an acidic medium (H+) to produce glucose (C6H12O6) and fructose (C6H12O6). **Hint**: Identify the reactants and products in the chemical equation. 2. **Determine the Order of Reaction**: The reaction involves two reactants: sucrose and water. Initially, it may seem like a second-order reaction since there are two reactants. **Hint**: Consider the number of reactants when determining the order of the reaction. 3. **Consider the Role of Water**: In hydrolysis reactions, water is typically present in excess. This means that its concentration does not change significantly during the reaction. **Hint**: Think about how the concentration of water affects the rate of the reaction. 4. **Express the Rate Law**: The general form of the rate law can be written as: \[ R = k[\text{sucrose}][\text{water}] \] However, since water is in excess, we can treat its concentration as a constant. Thus, we can define a new rate constant \( k' = k[\text{water}] \). **Hint**: Remember that when a reactant is in excess, its concentration can be treated as a constant. 5. **Final Rate Law**: The rate law can now be simplified to: \[ R = k'[\text{sucrose}] \] This indicates that the reaction is pseudo-first-order with respect to sucrose. **Hint**: Simplify the rate law by substituting constants for concentrations that do not change. 6. **Conclusion**: The rate law for the hydrolysis of sucrose is dependent only on the concentration of sucrose and not on water, confirming that it is a pseudo-first-order reaction. **Hint**: Conclude by summarizing how the reaction behaves based on the concentrations of the reactants. ### Summary: The rate law for the reaction of sucrose hydrolysis in the presence of water and H+ is: \[ R = k'[\text{sucrose}] \] where \( k' \) is a modified rate constant that includes the concentration of water, treated as constant due to its excess.
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