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The order of a reaction which has the ra...

The order of a reaction which has the rate expression `(dc)/(dt) = k[E]^(3//2)[D]^(3//2)` is

A

`3//2`

B

3

C

2

D

0

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To determine the order of the reaction from the given rate expression, we will follow these steps: ### Step 1: Identify the rate expression The rate expression given is: \[ \frac{dc}{dt} = k[E]^{\frac{3}{2}}[D]^{\frac{3}{2}} \] Here, \( k \) is the rate constant, and \([E]\) and \([D]\) are the concentrations of the reactants. ### Step 2: Determine the order with respect to each reactant The order of a reaction with respect to a reactant is determined by the exponent of that reactant in the rate expression. - For reactant \( E \): - The exponent is \( \frac{3}{2} \), so the order with respect to \( E \) is \( \frac{3}{2} \). - For reactant \( D \): - The exponent is also \( \frac{3}{2} \), so the order with respect to \( D \) is \( \frac{3}{2} \). ### Step 3: Calculate the overall order of the reaction The overall order of the reaction is the sum of the orders with respect to each reactant: \[ \text{Overall order} = \text{Order with respect to } E + \text{Order with respect to } D \] Substituting the values we found: \[ \text{Overall order} = \frac{3}{2} + \frac{3}{2} = \frac{6}{2} = 3 \] ### Conclusion The overall order of the reaction is \( 3 \). ---
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