Deuterons when bombarded on a nuclide produce`Ar_18^38` and neutrons. The target is:

Options

A. `Cl_17^35`
B. `K_19^27`
C. `Cl_17^37`
D. `K_19^39`

Answer

To solve the problem, we need to identify the target nuclide (X) that, when bombarded with deuterons (\( ^2_1H \)), produces Argon-38 (\( ^{38}_{18}Ar \)) and neutrons (\( ^1_0n \)). We will follow these steps:

### Step 1: Write the Nuclear Reaction
The nuclear reaction can be represented as:
\[ X + ^2_1H \rightarrow ^{38}_{18}Ar + ^1_0n \]

### Step 2: Identify the Mass and Atomic Numbers
- For Argon-38, the mass number (A) is 38 and the atomic number (Z) is 18.
- For a neutron, the mass number (A) is 1 and the atomic number (Z) is 0.
- Let the target nuclide \( X \) have mass number \( A \) and atomic number \( Z \).

### Step 3: Balance the Atomic Numbers
The total atomic number on the left side must equal the total atomic number on the right side:
\[ Z + 1 = 18 + 0 \]
This simplifies to:
\[ Z + 1 = 18 \]
Thus,
\[ Z = 17 \]

### Step 4: Balance the Mass Numbers
Now, we balance the mass numbers:
\[ A + 2 = 38 + 1 \]
This simplifies to:
\[ A + 2 = 39 \]
Thus,
\[ A = 39 - 2 = 37 \]

### Step 5: Identify the Nuclide
Now we have found:
- Mass number \( A = 37 \)
- Atomic number \( Z = 17 \)

The nuclide can be represented as \( ^{37}_{17}X \).

### Step 6: Determine the Element
The element with atomic number 17 is Chlorine (Cl). Therefore, the target nuclide \( X \) is:
\[ ^{37}_{17}Cl \]

### Final Answer
The target nuclide is \( ^{37}_{17}Cl \).

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