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C6^14 is formed from N7^14in the upper a...

`C_6^14` is formed from `N_7^14`in the upper atmosphere by the action of the fundamental particle

A

Positron

B

Neutron

C

Electron

D

Proton

Text Solution

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To solve the question regarding the formation of Carbon-14 from Nitrogen-14 in the upper atmosphere, we will analyze the nuclear reaction involved step by step. ### Step-by-Step Solution: 1. **Identify the Reactants and Products:** - The reactant is Nitrogen-14, represented as \( ^{14}_{7}N \). - The product is Carbon-14, represented as \( ^{14}_{6}C \). - A fundamental particle, which we will identify, is involved in this reaction. 2. **Understand the Composition of the Nuclei:** - Nitrogen-14 has a mass number of 14 and an atomic number of 7. This means it has 7 protons and \( 14 - 7 = 7 \) neutrons. - Carbon-14 has a mass number of 14 and an atomic number of 6. This means it has 6 protons and \( 14 - 6 = 8 \) neutrons. 3. **Determine the Fundamental Particle Involved:** - The reaction involves a neutron, which is represented as \( ^{1}_{0}n \) (mass number 1, atomic number 0). - When a neutron collides with Nitrogen-14, it causes a transformation. 4. **Write the Nuclear Reaction:** - The reaction can be written as: \[ ^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H \] - Here, \( ^{1}_{1}H \) represents a hydrogen atom (or a proton). 5. **Check Conservation of Mass and Atomic Numbers:** - On the left side: - Mass number: \( 14 + 1 = 15 \) - Atomic number: \( 7 + 0 = 7 \) - On the right side: - Mass number: \( 14 + 1 = 15 \) - Atomic number: \( 6 + 1 = 7 \) - Both mass and atomic numbers are balanced, confirming the reaction is valid. 6. **Conclusion:** - The fundamental particle that acts on Nitrogen-14 to form Carbon-14 is a neutron. ### Final Answer: The fundamental particle is a **neutron**.
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Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . A nuclear explosion has taken place leading to an increase in the concentration of C^(14) in nearby areas. C^(14) concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is determined to be T_(1) and T_(2) at the places , respectively, then

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . What should be the age of fossil for meaningful determination of its age ?

Consider the beta decay of an unstable ._(6)^(14)C nuleus initially at rest: ._(6)^(14)C rarr ._(7)^(14)N +._(-1)^(0)e +v._(e) . Is it possible for the maximum kinetic energy of the emiited beta particle to be exactly equal to Q ?

A certain nucleus X has a mass number 14 and atomic number 6. The nucleus X changes to ""_(7)Y^(14) after the loss of a particle. Name the particle emitted.

The bombarment of alpha - particle on ""_7N^14 , emits proton then new atom will be :