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In the given reaction, U92^235overset(-a...

In the given reaction, `U_92^235overset(-alpha)to (A) overset(-beta)to(B) overset(-beta)to ©` isotope are :

A

A and C

B

`U_92^235`

C

A and B

D

A, B and C

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the decay process of Uranium-235 (U-235) and determine the isotopes formed at each stage. ### Step 1: Identify the initial isotope The initial isotope is Uranium-235, represented as: \[ U_{92}^{235} \] ### Step 2: Alpha decay of U-235 In alpha decay, an alpha particle (which consists of 2 protons and 2 neutrons) is emitted. This results in: - The mass number decreases by 4 (because of the 4 nucleons in the alpha particle). - The atomic number decreases by 2 (because of the 2 protons in the alpha particle). Calculating the new isotope: - New mass number = 235 - 4 = 231 - New atomic number = 92 - 2 = 90 Thus, after alpha decay, the new isotope A is: \[ A_{90}^{231} \] ### Step 3: Beta decay of A In beta decay, a neutron is converted into a proton, and a beta particle (an electron) is emitted. This results in: - The mass number remains the same. - The atomic number increases by 1. Calculating the new isotope: - New mass number = 231 (remains the same) - New atomic number = 90 + 1 = 91 Thus, after the first beta decay, the new isotope B is: \[ B_{91}^{231} \] ### Step 4: Beta decay of B B undergoes another beta decay, which again results in: - The mass number remains the same. - The atomic number increases by 1. Calculating the new isotope: - New mass number = 231 (remains the same) - New atomic number = 91 + 1 = 92 Thus, after the second beta decay, the new isotope C is: \[ C_{92}^{231} \] ### Step 5: Identify isotopes Isotopes are defined as atoms of the same element (same atomic number) that have different mass numbers. From our calculations: - U-235 has atomic number 92 and mass number 235. - C has atomic number 92 and mass number 231. Thus, the isotopes are: 1. U-235 (Uranium-235) 2. C-231 (Uranium-231) ### Final Answer The isotopes are: - \( U_{92}^{235} \) (Uranium-235) - \( C_{92}^{231} \) (Uranium-231) ---
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