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A radioactive substance takes 20 min to ...

A radioactive substance takes 20 min to decay 25%. How much time will be taken to decay 75% :

A

96.4 min

B

68 min

C

964 min

D

680 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much time it takes for a radioactive substance to decay 75% when it takes 20 minutes to decay 25%, we can use the principles of first-order kinetics. Here’s a step-by-step solution: ### Step 1: Understand the decay process Radioactive decay follows first-order kinetics, which means the rate of decay is proportional to the amount of substance that remains. The formula for first-order kinetics is: \[ k = \frac{2.303}{t} \log \left( \frac{A_0}{A_t} \right) \] Where: - \( k \) is the rate constant, - \( A_0 \) is the initial amount, - \( A_t \) is the amount remaining after time \( t \). ### Step 2: Calculate the rate constant \( k \) Given that the substance decays 25% in 20 minutes, we can set: - \( A_0 = 100 \) (initial amount), - \( A_t = 100 - 25 = 75 \) (amount remaining after 25% decay), - \( t = 20 \) minutes. Now substituting these values into the formula: \[ k = \frac{2.303}{20} \log \left( \frac{100}{75} \right) \] Calculating the logarithm: \[ \log \left( \frac{100}{75} \right) = \log(1.3333) \approx 0.1249 \] Now substituting this back into the equation for \( k \): \[ k = \frac{2.303}{20} \times 0.1249 \] Calculating \( k \): \[ k \approx \frac{2.303 \times 0.1249}{20} \approx 0.01438 \, \text{min}^{-1} \] ### Step 3: Calculate the time for 75% decay Now we want to find out how long it takes to decay 75%. If 75% has decayed, then 25% remains: - \( A_t = 100 - 75 = 25 \). Using the same formula for \( t \): \[ t = \frac{2.303}{k} \log \left( \frac{A_0}{A_t} \right) \] Substituting the values: \[ t = \frac{2.303}{0.01438} \log \left( \frac{100}{25} \right) \] Calculating the logarithm: \[ \log \left( \frac{100}{25} \right) = \log(4) \approx 0.6021 \] Now substituting this back into the equation for \( t \): \[ t = \frac{2.303}{0.01438} \times 0.6021 \] Calculating \( t \): \[ t \approx \frac{2.303 \times 0.6021}{0.01438} \approx 96.4 \, \text{minutes} \] ### Final Answer The time taken to decay 75% of the radioactive substance is approximately **96.4 minutes**. ---
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