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The variation of rate constant with temp...

The variation of rate constant with temperature is given by the integrated from of the Arrhenius equation, `log_10k = (-Ea)/(2.303 RT)` + constant
where k = rate cosntant and Ea is the experimental activation energy. If for a certain reaction, `log_10k = (-3163.0)/T + 11.899`, calculate Ea.

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AI Generated Solution

To solve the problem, we need to calculate the activation energy (Ea) using the provided equation from the Arrhenius equation. The given equation is: \[ \log_{10} k = \frac{-3163.0}{T} + 11.899 \] ### Step-by-Step Solution: 1. **Identify the Form of the Equation:** We recognize that the equation given can be compared to the integrated form of the Arrhenius equation: ...
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