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The energy change accompanying the equil...

The energy change accompanying the equilibrium reaction `A hArrB` is `-33.0kJ mol^(-1)`. Calculate Energy of activation for forward and backward reaction `(E_f and E_a)` at 300 K. Given that `E_f and E_b` are in the ratio 20 : 31. Assume that pre-exponential factor is same for forward and backward reaction.

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To solve the problem, we need to calculate the energy of activation for the forward reaction (E_f) and the backward reaction (E_b) using the information provided. ### Step-by-Step Solution: 1. **Understanding the Reaction and Given Data:** - The equilibrium reaction is \( A \rightleftharpoons B \). - The energy change (\( \Delta H \)) for the reaction is given as \( -33.0 \, \text{kJ mol}^{-1} \). - The ratio of the activation energies for the forward and backward reactions is given as \( E_f : E_b = 20 : 31 \). ...
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