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Ferric hydroxide sol is positively charg...

Ferric hydroxide sol is positively charged colloid. The coagulating power of `NO_3^-, SO_4^(2-) and PO_4^(3-)` ions would be in the order

A

`NO_3^(-) gt SO_4^(2-) gt PO_4^(3-)`

B

`SO_4^(2-) gt NO_3^(-) gt PO_4^(3-)`

C

`PO_4^(3-) gt SO_4^(2-) gt NO_3^-`

D

`NO_3^(-) = SO_4^(2-) =PO_4^(3-)`

Text Solution

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The correct Answer is:
To determine the coagulating power of the ions \( \text{NO}_3^- \), \( \text{SO}_4^{2-} \), and \( \text{PO}_4^{3-} \) on the positively charged colloid of ferric hydroxide, we can follow these steps: ### Step 1: Understand the Concept of Coagulation Coagulation refers to the process where colloidal particles aggregate to form a precipitate. The coagulating power of an ion is influenced by its charge and valency. According to Hardy-Schulze rule, ions with higher valency have greater coagulating power. ### Step 2: Identify the Valency of Each Ion - For \( \text{NO}_3^- \): The valency is 1 (it carries a single negative charge). - For \( \text{SO}_4^{2-} \): The valency is 2 (it carries two negative charges). - For \( \text{PO}_4^{3-} \): The valency is 3 (it carries three negative charges). ### Step 3: Compare the Coagulating Power Based on Valency Since the coagulating power increases with the valency of the ions, we can rank the ions based on their valency: - \( \text{PO}_4^{3-} \) has the highest valency (3), thus it has the highest coagulating power. - \( \text{SO}_4^{2-} \) has the next highest valency (2), thus it has moderate coagulating power. - \( \text{NO}_3^- \) has the lowest valency (1), thus it has the lowest coagulating power. ### Step 4: Write the Final Order of Coagulating Power Based on the above analysis, the order of coagulating power from highest to lowest is: \[ \text{PO}_4^{3-} > \text{SO}_4^{2-} > \text{NO}_3^- \] ### Conclusion Thus, the coagulating power of \( \text{NO}_3^- \), \( \text{SO}_4^{2-} \), and \( \text{PO}_4^{3-} \) ions would be in the order: \[ \text{PO}_4^{3-} > \text{SO}_4^{2-} > \text{NO}_3^- \]
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