The following compound is obtained when `CH_(3)CH_(2)CHBr_(2)` is boiled with aqueous caustic potash:

Options

A. `CH_(3)-C -= CH`
B. `CH_(3)-CH=CHBr`
C. `CH_(3)CH_(2)CHO`
D. None of these

Explanation

To solve the problem of determining the compound obtained when `CH3CH2CHBr2` is boiled with aqueous caustic potash (KOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The compound we are starting with is `CH3CH2CHBr2`, which is 1-bromo-2-bromopropane. When this compound is treated with aqueous KOH, the KOH acts as a strong base.

**Hint**: Recognize that KOH will provide hydroxide ions (OH⁻) that can participate in nucleophilic substitution reactions.

2. **Understand the Reaction Type**:
The reaction between `CH3CH2CHBr2` and KOH will primarily proceed via an SN2 mechanism due to the presence of the strong nucleophile (OH⁻) and the steric accessibility of the bromine atoms.

**Hint**: Recall that SN2 reactions involve a nucleophile attacking the electrophilic carbon, leading to the displacement of a leaving group (in this case, bromine).

3. **Nucleophilic Attack**:
The hydroxide ion (OH⁻) will attack one of the bromine-bearing carbons. Since there are two bromine atoms, we can expect the reaction to proceed with the displacement of one of the bromine atoms first.

The reaction can be represented as follows:
\[ CH3CH2CHBr2 + OH⁻ \rightarrow CH3CH2CHBr(OH) + Br⁻ \]
This results in the formation of a bromo-alcohol intermediate.

**Hint**: Keep track of the bromine atoms and the hydroxyl group as they are crucial to the final product.

4. **Dehydration**:
The next step involves the removal of water (dehydration) from the bromo-alcohol intermediate. This can occur under the reaction conditions, leading to the formation of an aldehyde.

The dehydration can be represented as:
\[ CH3CH2CHBr(OH) \rightarrow CH3CH2C(=O)H + HBr \]
Here, the compound formed is propanal (an aldehyde).

**Hint**: Remember that dehydration reactions often lead to the formation of carbonyl compounds (like aldehydes or ketones).

5. **Final Product**:
The final product obtained from the reaction of `CH3CH2CHBr2` with aqueous KOH is propanal (CH3CH2CHO).

**Hint**: Verify the structure of the final product to ensure it matches the expected outcome of the reaction.

### Conclusion:
The compound obtained when `CH3CH2CHBr2` is boiled with aqueous caustic potash is propanal (CH3CH2CHO).