Benzene diazoniumtetrafluoro borate `overset(Delta) to` Product (A) . In the above process product A is

Options

A. Fluorobenzene
B. Benzene
C. 1, 4- difluorobenzene
D. 1, 3- difluorobenzene

Answer

To determine the product A formed from benzene diazonium tetrafluoroborate upon heating, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Starting Material**:
The starting material is benzene diazonium tetrafluoroborate, which can be represented as C6H5N2+BF4-. This compound is derived from the diazotization of an aromatic amine.

2. **Understand the Reaction Conditions**:
The problem states that the compound is heated. Heating typically induces a reaction that leads to the elimination of nitrogen gas (N2), which is a common behavior of diazonium salts.

3. **Elimination of Nitrogen**:
Upon heating, the diazonium group (N2+) is a good leaving group. Therefore, when benzene diazonium tetrafluoroborate is heated, it will lose the N2 gas.

4. **Formation of the Product**:
The remaining part of the molecule after the loss of N2 is the fluorobenzene. The BF4- ion remains intact, and one of the fluorine atoms from the tetrafluoroborate can attach to the benzene ring.

5. **Final Product**:
The final product A is thus fluorobenzene (C6H5F). The overall reaction can be summarized as:
\[ C6H5N2^+BF4^- \xrightarrow{\Delta} C6H5F + N2 + BF3 \]

### Conclusion:
The product A formed from the heating of benzene diazonium tetrafluoroborate is **fluorobenzene (C6H5F)**.

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