`C_(6)H_(6)+CI_(2)overset(UVLight)rarr` Product In above reaction product is .

Options

A. `"CCl"_(3)CHO`
B. `C_(6)H_(6)Cl_(6)`
C. `C_(6)H_(12)Cl_(6)`
D. `C_(6)H_(9)Cl_(2)`

Answer

To solve the question regarding the reaction of benzene (C₆H₆) with chlorine (Cl₂) in the presence of UV light, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
The reactants in this reaction are benzene (C₆H₆) and chlorine gas (Cl₂).

2. **Understand the Reaction Conditions:**
The reaction takes place in the presence of UV light, which indicates that it is a photochemical reaction. UV light provides the energy needed to initiate the reaction.

3. **Recognize the Type of Reaction:**
This reaction is known as the chlorination of benzene. In this process, chlorine atoms will replace hydrogen atoms in the benzene ring.

4. **Mechanism of the Reaction:**
- The UV light causes the Cl-Cl bond in Cl₂ to break, forming two chlorine radicals (Cl·).
- These chlorine radicals can then react with benzene. Since benzene has a stable aromatic structure, the chlorine radicals will substitute hydrogen atoms in the benzene ring.

5. **Formation of the Product:**
Each hydrogen atom in benzene can be replaced by a chlorine atom. Since benzene has six hydrogen atoms, the complete substitution will lead to the formation of hexachlorobenzene.

6. **Write the Chemical Equation:**
The balanced chemical equation for this reaction can be represented as:
\[ C_6H_6 + 3Cl_2 \xrightarrow{UV \, light} C_6Cl_6 + 3HCl \]
However, in the context of complete chlorination, we can also represent it as:
\[ C_6H_6 + 6Cl_2 \xrightarrow{UV \, light} C_6H_6Cl_6 \]

7. **Identify the Product:**
The product formed is benzene hexachloride, represented as C₆H₆Cl₆.

### Final Answer:
The product of the reaction between benzene (C₆H₆) and chlorine (Cl₂) in the presence of UV light is benzene hexachloride (C₆H₆Cl₆).

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