Reaction of ethyl chloride with sodium leads to :

Options

A. Ethane
B. Propane
C. n - butane
D. n - pentane

Answer

To solve the question regarding the reaction of ethyl chloride with sodium, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are ethyl chloride (C2H5Cl) and sodium (Na).

2. **Understand the Reaction Type**: This reaction is known as the Wurtz reaction. It involves the coupling of alkyl halides in the presence of sodium to form higher alkanes.

3. **Write the Reaction**: When ethyl chloride reacts with sodium, the reaction can be represented as:
\[ 2 \text{C}_2\text{H}_5\text{Cl} + 2 \text{Na} \rightarrow \text{C}_4\text{H}_{10} + 2 \text{NaCl} \]

4. **Identify the Product**: The product formed from the coupling of two ethyl groups (C2H5) is butane (C4H10). Specifically, it is n-butane, which has the structural formula CH3-CH2-CH2-CH3.

5. **Conclusion**: Therefore, the reaction of ethyl chloride with sodium leads to the formation of n-butane.

### Final Answer:
The reaction of ethyl chloride with sodium leads to **n-butane (Option C)**.

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