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Rate law for the elementary reaction 2AB...

Rate law for the elementary reaction `2AB to^(k_1) A_2+B_2` will be:

A

Rate =`-(d[AB])/(dt)=k_1[AB]^2`

B

Rate =`-(d[A_2])/(dt)=k_1[AB]^2`

C

Rate =`(d[B_2])/(dt)=k_1[AB]^2`

D

Rate =`-(d[A_2])/(dt)=(k_1[AB]^2)/2`

Text Solution

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The correct Answer is:
To determine the rate law for the elementary reaction \(2AB \xrightarrow{k_1} A_2 + B_2\), we can follow these steps: ### Step 1: Identify the Reaction The given reaction is \(2AB \xrightarrow{k_1} A_2 + B_2\). This indicates that two moles of \(AB\) react to form one mole of \(A_2\) and one mole of \(B_2\). **Hint:** Look at the stoichiometry of the reactants and products to understand the relationship between them. ### Step 2: Understand Elementary Reactions An elementary reaction is a reaction that occurs in a single step. For elementary reactions, the rate law can be directly derived from the stoichiometry of the reaction. **Hint:** Remember that for elementary reactions, the molecularity is equal to the order of the reaction. ### Step 3: Determine Molecularity In this reaction, there are 2 moles of \(AB\) on the reactant side. Therefore, the molecularity of this reaction is 2. **Hint:** Count the number of reactant molecules involved in the elementary step to find the molecularity. ### Step 4: Write the Rate Law Since the molecularity is 2, the rate law can be expressed in terms of the concentration of the reactant \(AB\). The rate law is given by: \[ \text{Rate} = k_1 [AB]^n \] where \(n\) is the molecularity of the reaction. Here, \(n = 2\). **Hint:** Use the molecularity to determine the exponent in the rate law expression. ### Step 5: Final Rate Law Expression Substituting \(n = 2\) into the rate law expression, we get: \[ \text{Rate} = k_1 [AB]^2 \] This means the rate of the reaction is proportional to the square of the concentration of \(AB\). **Hint:** Ensure that you include the rate constant \(k_1\) and the correct concentration term in your final expression. ### Conclusion Thus, the rate law for the elementary reaction \(2AB \xrightarrow{k_1} A_2 + B_2\) is: \[ \text{Rate} = k_1 [AB]^2 \]
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