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The rate of disapperance of Q in the rea...

The rate of disapperance of Q in the reaction `2P+Q to 2R+3S` is `2 times 10^-2` moles `l^-1 s^-1`. Which of the following statement is not true?

A

`-(d[P])/(dt)=4 times 10^-2 moles l^-1 s^-1`

B

`+(d[S])/(dt)=6times 10^-2 moles l^-1 s^-1`

C

`+1/2 (d[R])/(dt)=2 times 10^-2 moles l^-1 s^-1`

D

`+(d[R])/(dt)=2 times 10^-2 moles l^-1 s^-1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction and the given rate of disappearance of Q. The reaction is: \[ 2P + Q \rightarrow 2R + 3S \] We are given that the rate of disappearance of Q is: \[ -\frac{d[Q]}{dt} = 2 \times 10^{-2} \, \text{moles} \, \text{l}^{-1} \, \text{s}^{-1} \] ### Step 1: Write the rate expressions for the reaction. From the stoichiometry of the reaction, we can express the rates of disappearance and formation as follows: - For P: \[ -\frac{1}{2} \frac{d[P]}{dt} \] - For Q: \[ -\frac{d[Q]}{dt} \] - For R: \[ \frac{1}{2} \frac{d[R]}{dt} \] - For S: \[ \frac{1}{3} \frac{d[S]}{dt} \] ### Step 2: Relate the rates to the given rate of disappearance of Q. Since we know that: \[ -\frac{d[Q]}{dt} = 2 \times 10^{-2} \] We can find the rates of disappearance of P and formation of R and S. ### Step 3: Calculate the rate of disappearance of P. From the stoichiometric relationship: \[ -\frac{1}{2} \frac{d[P]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \(-\frac{d[Q]}{dt}\): \[ -\frac{1}{2} \frac{d[P]}{dt} = 2 \times 10^{-2} \] Thus, \[ \frac{d[P]}{dt} = -4 \times 10^{-2} \, \text{moles} \, \text{l}^{-1} \, \text{s}^{-1} \] ### Step 4: Calculate the rate of formation of R. From the stoichiometric relationship: \[ \frac{1}{2} \frac{d[R]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \(-\frac{d[Q]}{dt}\): \[ \frac{1}{2} \frac{d[R]}{dt} = 2 \times 10^{-2} \] Thus, \[ \frac{d[R]}{dt} = 4 \times 10^{-2} \, \text{moles} \, \text{l}^{-1} \, \text{s}^{-1} \] ### Step 5: Calculate the rate of formation of S. From the stoichiometric relationship: \[ \frac{1}{3} \frac{d[S]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \(-\frac{d[Q]}{dt}\): \[ \frac{1}{3} \frac{d[S]}{dt} = 2 \times 10^{-2} \] Thus, \[ \frac{d[S]}{dt} = 6 \times 10^{-2} \, \text{moles} \, \text{l}^{-1} \, \text{s}^{-1} \] ### Step 6: Evaluate the statements. Now we can evaluate the statements based on our calculations: 1. **Statement 1**: \(-\frac{d[P]}{dt} = 4 \times 10^{-2}\) (True) 2. **Statement 2**: \(\frac{d[S]}{dt} = 6 \times 10^{-2}\) (True) 3. **Statement 3**: \(\frac{1}{2} \frac{d[R]}{dt} = 2 \times 10^{-2}\) (True) 4. **Statement 4**: \(\frac{d[R]}{dt} = 2 \times 10^{-2}\) (False, it should be \(4 \times 10^{-2}\)) ### Conclusion The statement that is not true is **Statement 4**. ---
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