`k_(t+10)//k_1` is known as:

Options

A. Ratio of equilibrium constants
B. Temperature coefficient
C. Difference in temperature of reversible reactions
D. None of these

Answer

To solve the question regarding the expression \( \frac{k_{T+10}}{k_T} \), we will follow these steps:

### Step 1: Understand the Variables
- Here, \( k_T \) represents the rate constant at a certain temperature \( T \).
- \( k_{T+10} \) represents the rate constant at a temperature that is 10 degrees higher than \( T \).

### Step 2: Identify the Relationship
- The relationship between the rate constants at different temperatures can be expressed using the temperature coefficient \( \theta \).
- The temperature coefficient \( \theta \) is defined as the factor by which the rate constant changes when the temperature is increased by 10 degrees Celsius.

### Step 3: Use the Temperature Coefficient Formula
- The formula relating the rate constants at two temperatures is given by:
\[ \frac{k_{T+10}}{k_T} = \theta^{\Delta T/10} \]
- In this case, \( \Delta T = 10 \) (since we are increasing the temperature by 10 degrees).

### Step 4: Substitute the Values
- Substitute \( \Delta T = 10 \) into the equation:
\[ \frac{k_{T+10}}{k_T} = \theta^{10/10} = \theta^1 = \theta \]

### Step 5: Conclusion
- Therefore, \( \frac{k_{T+10}}{k_T} \) is equal to \( \theta \), which is known as the temperature coefficient.

### Final Answer
Thus, \( \frac{k_{T+10}}{k_T} \) is known as the **temperature coefficient**.

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