The order of a reaction with rate law, Rate=`kC_A^(3//2) C_B^(1//2)` will be:

Options

A. 2
B. 1
C. `-1/2`
D. `3/2`

Answer

To determine the order of the reaction based on the given rate law, we can follow these steps:

### Step 1: Write down the rate law expression
The rate law is given as:
\[ \text{Rate} = k C_A^{3/2} C_B^{1/2} \]

### Step 2: Identify the powers of the concentrations
In the rate law expression, the powers of the concentrations of the reactants \( C_A \) and \( C_B \) are:
- For \( C_A \): the power is \( \frac{3}{2} \)
- For \( C_B \): the power is \( \frac{1}{2} \)

### Step 3: Sum the powers to find the order of the reaction
The order of the reaction is the sum of the powers of the concentration terms in the rate law:
\[ \text{Order} = \left(\frac{3}{2}\right) + \left(\frac{1}{2}\right) \]

### Step 4: Calculate the total order
Calculating the sum:
\[ \text{Order} = \frac{3}{2} + \frac{1}{2} = \frac{3 + 1}{2} = \frac{4}{2} = 2 \]

### Step 5: State the final answer
The order of the reaction is \( 2 \).