Home
Class 12
CHEMISTRY
If the temperature is increased by 10°C ...

If the temperature is increased by 10°C the rate of the reaction becomes:

A

Ten times more

B

Ten times less

C

Two times more

D

Two times less

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding how the rate of a reaction changes with a 10°C increase in temperature, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Temperature and Rate Constant**: - The rate of a chemical reaction is generally dependent on the rate constant (k). According to the Arrhenius equation, an increase in temperature typically increases the rate constant. 2. **Identify the Effect of Temperature Increase**: - It is commonly observed that for many reactions, the rate constant doubles with every 10°C increase in temperature. This is a general rule of thumb known as the temperature coefficient. 3. **Apply the Doubling Rule**: - If the temperature is increased by 10°C, we can say that the rate constant (k) will become \( k_2 = 2k_1 \), where \( k_1 \) is the rate constant at the initial temperature and \( k_2 \) is the rate constant after the temperature increase. 4. **Relate Rate to Rate Constant**: - The rate of the reaction is directly proportional to the rate constant. Therefore, if the rate constant doubles, the rate of the reaction will also double. - Mathematically, if the initial rate is \( R_1 = k_1[A] \) and the new rate after the temperature increase is \( R_2 = k_2[A] \), we can substitute \( k_2 \): \[ R_2 = 2k_1[A] = 2R_1 \] 5. **Conclusion**: - Thus, when the temperature is increased by 10°C, the rate of the reaction becomes two times more than the original rate. ### Final Answer: The rate of the reaction becomes **2 times more**.
Promotional Banner

Similar Questions

Explore conceptually related problems

The rate of a chemical reaction doubles for every 10^(@)C rise of temperature. If the temperature is raised by 50^(@)C , the rate of the reaction increases by about

A catalyst increases the rate of a reaction by:

In a zero-order reaction for every 10^(@) rise of temperature, the rate is doubled. If the temperature is increased from 10^(@)C to 100^(@)C , the rate of the reaction will become

On increasing the temperature by 10K, the rate of reaction becomes double. Which of the following is the most appropriate reason?

Assertion (A) : Equilibrium constant of a reaction increases if temperature is increased Reason (R) : The forward reaction becomes faster with increase of temperature.

If the rate of reaction increases by two times with every 10^@C rise in temperature, then if we raise the temperature by 40^@C , the new rate of the reaction will be :-

If the rate of reaction increases by 27 times , when temperature is increased by 30 K, then temperature coefficient of the reaction is

In the following reaction, A+B+Q⇌C+D the temperature is increased then concentration of the product will

A catalyst increases the rate of a chemical reaction by

The temperature coefficient of a reaction is 2. When the temperature is increases from 30 ^@C " to " 90^@C , the rate of reaction is increased by