Home
Class 12
CHEMISTRY
The half life of decompoistion of N(2)O(...

The half life of decompoistion of `N_(2)O_(5)` is a first order reaction represented by `N_(2)O_(5)rarrN_(2)O_(4)+1//2O_(2)`
After `15`min the volume of `O_(2)` produced is `9ml` and at the end of the reaction `35ml`. The rate constant is equal to

A

`1/15 In 35/44`

B

`1/15 In 44/26`

C

`1/15 In 44/35`

D

`1/15 In 35/26`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The compoistion of N_(2)O_(5) is a first order reaction represented by: N_(2)O_(5) rarr N_(2)O_(4) + 1//2O_(2) . After 20 min the volume of O_(2) profuced is 10 mL and at the end of the reaction 40 mL . The rate constant is equal to

For the first order reaction. N_2O_5(g) rightarrow N_2O_4(g) + 1/2 O_2 (g), the volume of O_2 produced is 15 mL and 40 mL after 8 minutes and at the end of the reaction respectively. The rate constant is equal to

For the first order reaction 2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)

For the gaseous reaction: N_(2)O_(4) rarr 2NO_(2)

The main products formed by the reaction of N_(2)O_(5) and H_(2)O_(2) are

For the reaction 2N_(2)O_(5 )rarrNO_(2)+O_(2) rate of reaction is :

2N_(2)O_(5)to4NO_(2)+O_(2) . The rate of reaction in terms of N_(2)O_(5) will be

Half life of reaction : H_(2)O_(2)(aq) rarr H_(2)O(l)+(1)/(2)O_(2)(g) is independent of initial concentration of H_(2)O_(2) volume of O_(2) gas after 20 minute is 5L at 1 atm and 27^(@)C and after completion of reaction is 50L . The rate constant is :

For the reaction : 2N_(2)O_(5) rarr 4NO_(2) +O_(2) , the rate of reaction in terms of O_(2) is d[O_(2)] /dt. In terms of N_(2)O_(5) , it will be :

For a reaction, 2N_(2)O_(5)(g) to 4NO_(2)(g) + O_(2)(g) rate of reaction is: