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Ethyl alcohol is industrially prepared f...

Ethyl alcohol is industrially prepared from ethylene by:

A

Permanganate oxidation

B

Catalytic reduction

C

Absorbing in `H_(2)SO_(4)` followed by hydrolysis

D

Fermentation

Text Solution

AI Generated Solution

The correct Answer is:
To prepare ethyl alcohol (ethanol) from ethylene (ethene) industrially, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - We start with ethylene (C2H4), which can be represented as CH2=CH2. 2. **Reaction with Sulfuric Acid**: - Ethylene reacts with sulfuric acid (H2SO4). The double bond in ethylene allows it to undergo electrophilic addition. - The reaction can be written as: \[ \text{C}_2\text{H}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{C}_2\text{H}_5\text{HSO}_4 \] - This product is ethyl hydrogen sulfate (C2H5HSO4). 3. **Hydrolysis of Ethyl Hydrogen Sulfate**: - The next step is to hydrolyze ethyl hydrogen sulfate to produce ethyl alcohol. - The hydrolysis reaction can be represented as: \[ \text{C}_2\text{H}_5\text{HSO}_4 + \text{H}_2\text{O} \rightarrow \text{C}_2\text{H}_5\text{OH} + \text{H}_2\text{SO}_4 \] - This results in the formation of ethyl alcohol (C2H5OH) and regenerates sulfuric acid. 4. **Final Product**: - The final product of this reaction is ethyl alcohol (ethanol), which is the desired compound. ### Conclusion: The industrial preparation of ethyl alcohol from ethylene involves the reaction of ethylene with sulfuric acid to form ethyl hydrogen sulfate, followed by hydrolysis to yield ethyl alcohol. Therefore, the correct option is: **Option 3: Absorbing in sulfuric acid followed by hydrolysis.**
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