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10 gram of a solute was dissolved in 80 ...

10 gram of a solute was dissolved in 80 g of acetone at 30ºC to form an ideal solution. The vapour pressure was found to be 271 mm of Hg. Vapour pressure of pure acetone at `30^(@)` C is 283 mm Hg. The molecular weight of the solute is

A

100.5

B

120.5

C

150.5

D

163.5

Text Solution

Verified by Experts

The correct Answer is:
D
`(P_("Acetone")^(@)-P_("solution"))/(P_("Acetone")^(@))=X_("solute")implies(283-271)/283=("wt of solute/M.wt")/(("Wt. of Acetone")/(M.wt))`
`implies` M wt of solute `=163.5`
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