Home
Class 12
CHEMISTRY
A first order reaction takes 69.3 min fo...

A first order reaction takes 69.3 min for 50% completion. What is the time in min for 80% completion?

Text Solution

Verified by Experts

The correct Answer is:
A

`0.693/69.3=k`
`t=(2.303)/kxx"log"(R_(0))/Rimpliest=(2.303xx69.3)/0.693"log"100/20implies160.98` min
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 10

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 2)|5 Videos
  • MOCK TEST 1

    VMC MODULES ENGLISH|Exercise PART II : CHEMISTRY (SECTION-2)|10 Videos
  • MOCK TEST 11

    VMC MODULES ENGLISH|Exercise CHEMISTRY (Section-2)|5 Videos

Similar Questions

Explore conceptually related problems

(a) For a reaction A+BrarrP, the rate is given by Rate =K[A][B]^(2) (i) How is the rate of reaction affected if the concentration of B is doubled ? (ii) What is the overall order of reaction if A is present in large excess ? (b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.

A first order reaction takes 69.3 minutes for 50% completion. How much time will be needed for 80% completion?

A first order reaction is 20% complete in 10 min. What is the rate constant?

A zero-order reaction is 25% complete in 30seconds. What time does it take for 50% completion?

A first order reaction is 50% complete in 20 minutes. What is its rate constant ?

90% of a first order reaction was completed in 100 min . How much time it will take for 80% completion of a reaction

In the case of a first order reaction, the ratio of time required for 99.9% completion to 50% completion is

A first order reaction is 15% complete in 20 minutes. In what time will the reaction 60% complete ?