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A polarizer-analyser set is a adjusted ...

A polarizer-analyser set is a adjusted such that the intensity of light coming out of the analyser is just 12.5 % of the original intersity. Assuming that the polarizer – analyser set does not absorb any light the angle by which the analyser need to be rotated further to reduce the output intensity to be zero, is :

A

`45^(@)`

B

`90^(@)`

C

`60^(@)`

D

`30^(@)`

Text Solution

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The correct Answer is:
To solve the problem, we need to use Malus's Law, which states that the intensity of light passing through a polarizer-analyzer setup is given by: \[ I = I_0 \cos^2(\theta) \] where: - \( I \) is the transmitted intensity, - \( I_0 \) is the original intensity, - \( \theta \) is the angle between the light's polarization direction and the axis of the polarizer. ### Step-by-Step Solution: 1. **Identify the Given Information**: - The intensity of light coming out of the analyzer is 12.5% of the original intensity. - This can be expressed as: \[ I = 0.125 I_0 \] 2. **Apply Malus's Law**: - According to Malus's Law, after passing through the polarizer and analyzer, we can express the transmitted intensity as: \[ I = I_0 \cos^2(\theta) \] - Here, \( \theta \) is the angle between the polarizer and analyzer. 3. **Set Up the Equation**: - From the information given: \[ 0.125 I_0 = I_0 \cos^2(\theta) \] - We can cancel \( I_0 \) from both sides (assuming \( I_0 \neq 0 \)): \[ 0.125 = \cos^2(\theta) \] 4. **Solve for \( \theta \)**: - Taking the square root of both sides: \[ \cos(\theta) = \sqrt{0.125} = \frac{1}{2\sqrt{2}} \] - This simplifies to: \[ \cos(\theta) = \frac{1}{4} \] - Now, we find \( \theta \): \[ \theta = \cos^{-1}\left(\frac{1}{2}\right) \] - This gives: \[ \theta = 60^\circ \] 5. **Determine the Angle for Zero Intensity**: - To reduce the output intensity to zero, the angle between the polarizer and analyzer must be \( 90^\circ \). - Therefore, we need to find how much further the analyzer needs to be rotated: \[ \text{Angle to rotate} = 90^\circ - 60^\circ = 30^\circ \] ### Final Answer: The angle by which the analyzer needs to be rotated further to reduce the output intensity to zero is **30 degrees**. ---

To solve the problem, we need to use Malus's Law, which states that the intensity of light passing through a polarizer-analyzer setup is given by: \[ I = I_0 \cos^2(\theta) \] where: - \( I \) is the transmitted intensity, - \( I_0 \) is the original intensity, - \( \theta \) is the angle between the light's polarization direction and the axis of the polarizer. ...
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