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Visible light of wavelength 6000 x...

Visible light of wavelength 6000 ` xx 10 ^( - 8 ) ` cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at ` 60 ^(@) ` from the central maximum. If the first minimum is produced at ` theta _ 1`, then ` theta _ 1 ` is close to :

A

`40^(@)`

B

`35^(@)`

C

`30^(@)`

D

`15^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`a sin theta_(2)=3 lamda, a sin theta_(1)=lamda`
`(sin theta_(1))/(sin theta_(2))=1/3impliessin theta_(1)=(sin theta_(2))/3=(sin 45^(@))/3=1/(2sqrt(3))impliestheta_(1)~~15^(@)`
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