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If the equation |2 - x| - |x + 1| = k ha...

If the equation |2 - x| - |x + 1| = k has exactly one solution , then number of integral values of k is :

A

7

B

5

C

4

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
Let `f(x) = |x-2|-|x+1|={{:(3 , x lt -1) , ( -2x +1 , -1 le x le 2 ),(-3 , x gt 2):}`

So, ` k in ( -3, 3)
`:. k_("integers ") =-2, -1 , 0,1,2`
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