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If the shortest distance between 2y^(2)...

If the shortest distance between `2y^(2)-2x+1=0` and `2x^(2)-2y+1=0` is d then the number of solution of `|sin alpha|=2sqrt2 d(alpha in [-pi, 2pi])` is.

A

3

B

4

C

5

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`2y(dy)/(dx)=1`
`rArr (dy)/(dx)=(1)/(2y)=1 rArr y=(1)/(2)`

So `d= sqrt((1)/(16)+(1)/(16))= (1)/(2 sqrt(2))`
so `|sin alpha|=1`
so number of solution is 3
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