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If (1+x-2x^2)^(20)=a0a1x=a2x^2+a3x^3++a(...

If `(1+x-2x^2)^(20)=a_0a_1x=a_2x^2+a_3x^3++a_(40)x^(40),` then find the value of `a_1+a_3+a_5++a_(39)dot`

A

0

B

`(3^(10)-1)/(2)`

C

`3^(10)`

D

`4^(10)`

Text Solution

Verified by Experts

The correct Answer is:
C

Let `(1+x+x^(2))^(10)(1-x+x^(2))^(10)`
`=a_(0)+a_(1)x+a_(2)x^(2)+…..+a_(40)x^(40)`
It can be seen that the expansion does not contain any term containing odd power.
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