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If an ellipse passes through the point P...

If an ellipse passes through the point `P(-3, 3)` and it has vertices at `(+-6, 0)` , then the equation of the normal to it at P is:

A

`3x + y + 6 =0`

B

`2x + 3y -3=0`

C

`x+3y -6=0`

D

`x-2y +9=0`

Text Solution

Verified by Experts

The correct Answer is:
A
`x^2/(36) + (y^2)/(b^2) = 1`
P(-3,3) lies on (i) get `b^2 = 12`
`(x^2)/(36) + (y^2)/(12) =1 `
Equation of normal is `(a^2 x)/(x_1) - (b^2 y)/(y_1) = a^2 e^2 , 3x + y + 6=0`
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