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The value of Delta(f) H^(Θ) for NH(3) is...

The value of `Delta_(f) H^(Θ)` for `NH_(3)` is `-91.8 kJ mol^(-1)`. Calculate enthalpy change for the following reaction.
`2NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)`

Text Solution

Verified by Experts

The correct Answer is:
`-836`
`DeltaH_(r xx n)=DeltaH_(f)^(@) (N_(2)O,g)+3DeltaH_(f)^(@)(CO_(2), g)-(2DeltaH_(f)^(@)NO_(2),g)-3DeltaH_(f)^(@)(CO,g)`
`=81+3xx(-393)-2xx34-3(-110)`
`=81-1179-68+330=-836kJ`
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