Home
Class 12
CHEMISTRY
Two glass bulbs A and B at same temperat...

Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cock. Bulb A has a volume of `100 cm^(3)` and contained the gas while bulb B is empty. On opening the stop-cock, the pressure fell down to `20%` . The volume of the bulb B is :

Text Solution

Verified by Experts

The correct Answer is:
150

`P_(1)=1` atm
`P_(2)= 1 "atm" xx (40)/(100)=0.40` atm
`V_(1)=100cm^(3)`
`V_(2)=?`
At constant temperature, `P_(1)V_(1)=P_(2)V_(2)`
So `V_(2)=(P_(1)V_(1))/(2) =(1"atm" xx 100cm^(3))/(0.40"atm")=250cm^(3)`
Hence, the volume of bulb `B=(250-100)cm^(3)=150cm^(3)`
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 1

    VMC MODULES ENGLISH|Exercise PART II : CHEMISTRY (SECTION-2)|10 Videos
  • LIQUID SOLUTIONS

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE -L|10 Videos
  • MOCK TEST 10

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

Two glass bulbs A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100 cm^(3) and contained the gas, while bulb B was empty. On opening th stop cock. The pressure fell down to 40%. The volume of the bulb B must be:

Two glass bulbs x and y are connected by a very small tube having a stop - cock. Bulb X has a volume of 100cm^(3) and contained the gas, while bulb Y was empty. On opening the stop - cock, the pressure fell down to 60% . The volume of the bulb Y must be

Two electric bulbs A and B are rated as 60 W and 100 W . They are connected in parallel to the same source. Then,

Two glass bulbs of same volume containing a gas at NTP are connected by a very narrow tube. The pressure is 88.46cm of mercury when one bulb is kept in ice and the other in hot water. Calculate the temperature of the hot water.

Two electric bulbs A and B are rated 60 and 100 W , respectively. If they are connected in parallel to the same source , then

Two gases A and B having the same temperature 'T' , Same pressure 'P' and same volume 'V' are mixed . If the temperature of mixture is unchanged and the volume occupied by it is 'V//2' , then the pressure of the mixture will be

Two identical glass bulbs are interconnected by a thin glass tube. A gas is filled in these bulbs at N.T.P. If one bulb is placed in ice and another bulb is placed in hot bath, then the pressure of the gas becomes 1.5 times. The temperature of hot bath will be

A gas is filled in a cylinder fitted with piston at a constant temperature and pressure. Explain on the basis of kinetic theory : (i) The pressure of the gas increases by raising its temperature. (ii) On pulling the piston out, the pressure of the gas decreases. The pressure of an ideal gas filled in the bulb of a constant - volume gas thermomrter at 7^(@)C is 60 cm of mercury. What will be the pressure of the same volume of gas at 147^(@)C ?

two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at 0(@)C at a pressure of 76cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at 62^(@)C .What is the new value of the pressure inside the bulbs? The volume of the connecting tube is neigligible.

Initially bulb "a" contained oxygen gas at 27^(@)C and 950 mm of Hg and bulb "B" contained neon gas at 27^(@)C and 900 mm of Hg. These bulbs are connected by a narrow tube of negligible volume equipped with a stopcock and gases were allowed to mix-up freely. The pressure obtained in the combined system was found to be 910 mm of Hg. If volume of bulb B was measured to be 10 L, then find the volume of oxygen gas present initially in bulb "A" .