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The equilibrium constant K(p) for the ho...

The equilibrium constant `K_(p)` for the homogeneous reaction is `10^(-3)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction at `27^(@)C ("using" R=2 cal K^(-1) mol^(-1))` is

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The correct Answer is:
`4145.40`
`DeltaG^(@)= -2.303RT log K_(p)= -2.303xx2xx300 log 10^(-3)`
`= -2.303xx2xx300xx(-3)=4145.4"cal mol"^(-1)`
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