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A 0.0020 m aqueous solution of an ionic ...

A 0.0020 m aqueous solution of an ionic compound `Co(NH_(3))_(5)(NO_(2))Cl` freezes at `-0.00732^(@)C`. Number of mole of ionic compound produces on being dissolved in water will be `(K_(f)=-1.86^(@)C//m)`

Text Solution

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The correct Answer is:
1
`Delta T_(f)=iK_(f)xx m`
`i=(Delta T_(f))/(k_(f)xx m)=(0.00732)/(1.86xx0.0020)=1.96 ~~ 2` Hence, complex is `[Co(NH_(3))_(4)Cl_(2)]Cl`.
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